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I give some supplementary additional explanation to my question.

On 2017/11/08 18:49, Rikimaru Honjo wrote:
> Hello,
> 
> * I'm using Zuul v3 ver.2.5.3.dev1585.
> 
> I created a job which runs following two tasks for zuul v3.[1]
> 
> 1. Run tests on remote host which is created by Nodepool.
>     (In this time, "hosts" value is "all".)
> 2. Run zuul_return on localhost where is zuul-executor.
>     And, submit a URL of logs specified as "log_url" attribute to gerrit.
>     (In this time, "hosts" value is "localhost".)
> 
> In this case, task 2 won't be run if task 1 is failed.
> And, the below URL will be submitted to gerrit.

The pseudocode is this:

# task-1
- hosts: all
   tasks:
     - command: "Run tests"
       register: result
       ignore_errors: True

     - command: "Process after testing"
# task-2
- hosts: localhost
   tasks:
     - zuul_return:
       [...]
       when: result.rc == 1

In this case, the "result" value of task-1 is not passed to task-2.
So I'm planning to save "result" value to a local file.
Are there any other solutions?

> finger://<hostname of zuul-executor>/e8ce4c7f627a43689dd9ad4ecc43c881
> 
> How do you run "zuul_return" if the test task will be failed?
> 
> P.S.
> If I specified "ignore_errors:True" in task 1, task2 was run even if
> task1 was failed.
> But, the submitted result was "SUCCESS" in this case.
> 
> [1]
> I refered the following suggestion.
> http://lists.openstack.org/pipermail/openstack-infra/2017-October/005646.html

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Rikimaru Honjo
E-mail:honjo.rikimaru at po.ntt-tx.co.jp