Open Stack

Yeah I have watched that multiple times over the weekend, and has helped
very much.

So with respect to my example numbers, I am guessing that each partition
will land on every '41538374868278621028243970633760768' of the md5 space.

2^(128 - 13)

or

2^(128)/8192

Thanks!



On Tue, Aug 19, 2014 at 8:00 PM, John Dickinson <me at not.mn> wrote:

>
> https://swiftstack.com/blog/2012/11/21/how-the-ring-works-in-openstack-swift/
> is soemthing that should be able to give you a pretty complete overview of
> how the ring works in Swift and how data placement works.
>
> Let me know if you have more questions after you watch that video.
>
> --John
>
>
>
>
>
>
> On Aug 19, 2014, at 5:34 PM, Brent Troge <brenttroge2016 at gmail.com> wrote:
>
> >
> > Excuse this question and for lack of basic understanding. I dropped from
> school at 8th grade, so everything is basically self taught. Here goes.
> >
> > I am trying to figure out where each offset/partition is placed on the
> ring.
> >
> >
> > So If I have 50 drives with a weight of 100 each I come up with the
> below part power
> >
> > part power = log2(50 * 100) = 13
> >
> > Using that I then come up with the amount of partitions.
> >
> > partitions = 2^13 =  8192
> >
> > Now here is where my ignorance comes into play. How do I use these
> datapoints to determine where each offset is on the ring?
> >
> > I then guess that for each offset they will have a fixed range of values
> that map to that partition.
> >
> > So for example, for offset 1, all object URL md5 hashes that have a
> decimal value of 0 through 100 will go here(i just made up the range 0
> through 100, i have no idea what the range would be with respect to my
> given part-power, drive, etc).
> > _______________________________________________
> > Mailing list:
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> > Post to     : openstack at lists.openstack.org
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>
>
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