[openstack-dev] [ceilometer] The periodic task on openstack

Eoghan Glynn eglynn at redhat.com
Fri Nov 16 15:30:16 UTC 2012



> > > A follow-up for your discussion on IRC last night, I had a quick
> > > check of the loopingcall implementation, and seems there is
> > > really
> > > no time gurantee. Even if we adjust the interval for
> > > greenthread.sleep() dynamically, we also must make the metering
> > > periodic task always at the head.
> > > 
> > > I think we can enhance the periodic task to meet partially our
> > > requirement, like create a separated task type as high-priority,
> > > which should make sure no long-delay.
> > > 
> > > The only concern is, can we make sure the LoopingCall itself will
> > > be invoked on time after the greenthread.sleep(interval),
> > > considering the attribute of greenthread, or even python thread.
> > > 
> > > openstack/common/loopingcall.py-> LoopingCall(object):
> > > 
> > >                 while self._running:
> > >                     self.f(*self.args, **self.kw)
> > >                     if not self._running:
> > >                         break
> > >                     greenthread.sleep(interval)
> 
> Thanks for following this up!
> 
> So can I confirm that I've understood the basic issues here are
> that:
> 
>  (a) The time spent executing tasks is not accounted for when
>      determining how much time to sleep between task runs. So
>      for example if periodic_interval is set to N seconds, the
>      actual time between tasks is of the order of:
> 
>        N + \Sigma duration(task_i)/(1 + ticks for task_i)
> 
>      The more tasks with ticks=0, and the longer the task
>      duration, the more we skew away from tasks executing on
>      wall-clock boundaries.
> 
>  (b) There is no guarantee (beyond convention) that a task won't
>      take longer than periodic_interval/|tasks| to execute.
> 
>  (c) There is an indeterminate lag after the expiry of the sleep
>      interval before the LoopingCall thread is re-scheduled.
> 
> So could we at least address issue (a) by simply subtracting
> the duration of the last tasks run from the next sleep interval?
> 
> e.g. change LoopingCall.start()._inner() as follows:
> 
>     while self._running:
> +       start = datetime.datetime.now()
>         self.f(*self.args, **self.kw)
> +       end = datetime.datetime.now()
> +       delta = end - start
> +       elapsed = delta.seconds + delta.microseconds/(10 ** 6)
> +       delay = interval - elapsed
>         if not self._running:
>             break
> -       greenthread.sleep(interval)
> +       greenthread.sleep(delay if delay > 0 else 0)
> 
> I guess that's what you meant by adjusting the interval dynamically?

https://review.openstack.org/16310

Cheers,
Eoghan



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