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<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Jyoti,<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">The swift object server IPs are encoded in the swift rings. So the swift object server IPs must not change.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D">Gerry.<o:p></o:p></span></p>
<p class="MsoNormal"><span style="font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D"><o:p> </o:p></span></p>
<p class="MsoNormal"><b><span style="font-size:11.0pt;font-family:"Calibri","sans-serif"">From:</span></b><span style="font-size:11.0pt;font-family:"Calibri","sans-serif""> Jyoti Ranjan [mailto:jranjan@gmail.com]
<br>
<b>Sent:</b> 18 August 2014 19:43<br>
<b>To:</b> openstack@lists.openstack.org<br>
<b>Subject:</b> [Openstack] [Swift] IP address of Swift nodes : need help<o:p></o:p></span></p>
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<p class="MsoNormal">Hi,<o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">We are deploying Swift clusters where we do have IP addresses assigned to Swift nodes via DHCP. Curious to know, what will happen if IP address of a give node change that node is made part of Swift cluster. For e.g. let us assume that Swift
object node got IP 192.168.10.2 and later it changes to 192.168.10.9 because of DHCP. Will running Swift cluster get affected?<o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">In other words, is it necessary to use static IP for Swift nodes?<o:p></o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal"><o:p> </o:p></p>
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<p class="MsoNormal">Regards,<o:p></o:p></p>
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<p class="MsoNormal">Jyoti Ranjan<o:p></o:p></p>
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