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</o:shapelayout></xml><![endif]--></head><body lang=EN-GB link=blue vlink=purple><div class=WordSection1><p class=MsoNormal><span style='font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D'>+1 for “X not in Y”<o:p></o:p></span></p><p class=MsoNormal><span style='font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D'><o:p> </o:p></span></p><p class=MsoNormal><span style='font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D'>“not X in Y” requires one who doesn’t code python every day to stop and think, “X not in Y” is largely unambiguous.<o:p></o:p></span></p><p class=MsoNormal><span style='font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D'><o:p> </o:p></span></p><div style='border:none;border-left:solid blue 1.5pt;padding:0cm 0cm 0cm 4.0pt'><div><div style='border:none;border-top:solid #B5C4DF 1.0pt;padding:3.0pt 0cm 0cm 0cm'><p class=MsoNormal><b><span lang=EN-US style='font-size:10.0pt;font-family:"Tahoma","sans-serif"'>From:</span></b><span lang=EN-US style='font-size:10.0pt;font-family:"Tahoma","sans-serif"'> Dolph Mathews [mailto:dolph.mathews@gmail.com] <br><b>Sent:</b> 31 January 2013 14:53<br><b>To:</b> OpenStack Development Mailing List<br><b>Subject:</b> Re: [openstack-dev] "if X not in Y" vs. "if not X in Y" consensus?<o:p></o:p></span></p></div></div><p class=MsoNormal><o:p> </o:p></p><div><p class=MsoNormal>+1 for "X not in Y"<o:p></o:p></p><div><p class=MsoNormal><o:p> </o:p></p></div><div><p class=MsoNormal>"not X in Y" reads ambiguously to me.<o:p></o:p></p></div></div><div><p class=MsoNormal><br clear=all><o:p></o:p></p><div><div><p class=MsoNormal><o:p> </o:p></p></div><p class=MsoNormal>-Dolph<o:p></o:p></p></div><p class=MsoNormal style='margin-bottom:12.0pt'><o:p> </o:p></p><div><p class=MsoNormal>On Thu, Jan 31, 2013 at 8:45 AM, Ray Pekowski <<a href="mailto:pekowski@gmail.com" target="_blank">pekowski@gmail.com</a>> wrote:<o:p></o:p></p><div><div><p class=MsoNormal>On Thu, Jan 31, 2013 at 1:23 AM, Zhongyue Luo <<a href="mailto:zhongyue.nah@intel.com" target="_blank">zhongyue.nah@intel.com</a>> wrote:<o:p></o:p></p><div><div><p class=MsoNormal style='margin-bottom:12.0pt'>Ray, we are only considering in cases when evaluation of membership is needed.<o:p></o:p></p></div><div><p class=MsoNormal>The "if not flag" is an boolean evaluation of "flag" itself and has nothing to do with dict.<o:p></o:p></p></div><p class=MsoNormal><o:p> </o:p></p></div></div><div><p class=MsoNormal><br>In that case, I (sarcastically) promote a counter proposal for negating a dictionary membership check. It must be done in two lines, as follows:<o:p></o:p></p><div><p class=MsoNormal style='margin-bottom:12.0pt'><br><br>flag = key in dict<br>if not flag:<o:p></o:p></p></div><p class=MsoNormal>The following forms are disallowed due to the desire for conformity: "if key not in dict" and "if not key in dict".<br><br>Votes? :-)<o:p></o:p></p></div></div><p class=MsoNormal style='margin-bottom:12.0pt'><br>_______________________________________________<br>OpenStack-dev mailing list<br><a href="mailto:OpenStack-dev@lists.openstack.org">OpenStack-dev@lists.openstack.org</a><br><a href="http://lists.openstack.org/cgi-bin/mailman/listinfo/openstack-dev" target="_blank">http://lists.openstack.org/cgi-bin/mailman/listinfo/openstack-dev</a><o:p></o:p></p></div><p class=MsoNormal><o:p> </o:p></p></div></div></div></body></html>